tolong bntu ya kak mks
1.
besar sudut ∆ = 180⁰
sudut P = 90⁰
Q = 180 - 90 - 65 = 25⁰
2.
besar sudut ∆ = 180⁰
ket. dik. pada gambar ∆ menunjukkan
P = 20⁰, Q = 3x⁰, R = 5x⁰
P + Q + R = 180⁰
20⁰ + 3x⁰ + 5x⁰ = 180⁰
8x⁰ = 180⁰ - 20⁰
8x⁰ = 160⁰
x = 160⁰/8⁰
x = 20
sudut R = 5x⁰ = 5•20⁰ = 100⁰
sudut Q = 3x⁰ = 3•20⁰ = 60⁰
ket. dik. pada gambar ∆ menunjukkan
P = 20⁰, Q = 2x⁰, R = 4x⁰
P + Q + R = 180⁰
20⁰ + 2x⁰ + 4x⁰ = 180⁰
6x⁰ = 180⁰ - 20⁰
6x⁰ = 160⁰
x = 160⁰/6⁰
x = 26,67⁰
sudut R = 4x⁰ = 4•26,67⁰ = 106.68⁰
sudut Q = 2x⁰ = 2•26,67⁰ = 53,34⁰
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